172.16.0.0/23
11111111.11111111.11111110.00000000
netmask : 256 - 2^y= 256 - 2^1
256 - 2 = 254 {255.255.254.0}
1. berapa blok subnet:
256 -(netmask) = 256 -254 = 2
jadi blok (0,2,4,6 ...... 254)
2. Jumlah Host /subnet= 2^y = 2^9 = 512 Per subnet
3. Jumlah subnet = 2^x = 2^7 = 128 Subnet
4. ip per subnet :
subnet 1
network :172.16.0.0
range :172.16.0.1 s.d 172.16.1.254
broadcast :172.16.1.255
pembuktian subnet 1:
172.16.0.1
172.16.0.2
172.16.0.255
------------------256
172.16.1.0
172.16.1.1
172.16.1.255
------------------256
subnet ke 2
network : 172.16.2.0
range : 172.16.2.1 s.d 172.16.3.254
broadcast : 172.16.3.255